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is 7/12x the answer to 3/4x 1/6x?
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Are you adding or subtracting these fractions?
And is x in the denominator (for each fraction)?
dividing.
and yes
Is the first fraction \[\Large \frac{3}{4x}\] ???
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alright thanks
yw
3/(4x) ------ 1/(6x) really is ( 3/(4x) ) * ( (6x)/1 ) because when you divide fractions, you flip the second fraction and multiply
okay.
So multiply that last fraction out to get... ( 3/(4x) ) * ( (6x)/1 ) ( 3*6x )/( 4x*1 ) (18x)/(4x) 9/2
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okay thanks
yw
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