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Mathematics 22 Online
OpenStudy (anonymous):

Look at the figure shown below. What is the length of Segment AB to the nearest tenth of a meter?

OpenStudy (anonymous):

OpenStudy (anonymous):

this problem is not multiple choice; tips?

OpenStudy (kinggeorge):

Since \(\Delta \)ADC is a 30-60-90 triangle, you can find the lengths of AD and DC easily. Using the length of DC, and BC, you can use pythagorean theorem to get the length of DB. Length DB+AD =AB

OpenStudy (anonymous):

k

OpenStudy (anonymous):

ehh

OpenStudy (anonymous):

AD equals 8.082903769

OpenStudy (anonymous):

Side AB is 16.16580754

OpenStudy (anonymous):

Am I right so far?

OpenStudy (anonymous):

ahhh

OpenStudy (kinggeorge):

Give me minute

OpenStudy (anonymous):

there's a shortcut to 30-60-90 right triangles

OpenStudy (anonymous):

AD equals 7

OpenStudy (anonymous):

and DC equals 7 and the square root of 3

OpenStudy (anonymous):

and there you have it

OpenStudy (anonymous):

am I right?

OpenStudy (kinggeorge):

So far that looks right. What do you get for DB?

OpenStudy (anonymous):

well...

OpenStudy (anonymous):

I don't know if triangle CDB is a right triangle :(

OpenStudy (anonymous):

I think it is...

OpenStudy (anonymous):

IF so, angle C=30...

OpenStudy (anonymous):

Wait...

OpenStudy (anonymous):

Reflexive property of equality!!!!!!!!!!!!!!!

OpenStudy (anonymous):

Angle D=angle D

OpenStudy (anonymous):

so angle D=90 degrees

OpenStudy (anonymous):

Angle C=30

OpenStudy (anonymous):

And angle B=60 degrees

OpenStudy (anonymous):

so DB equals 6.5

OpenStudy (anonymous):

and DC equals 11.25833025

OpenStudy (anonymous):

so AB equals 7+6.5=13.5!!!!!!!!!!!

OpenStudy (anonymous):

AD=7 while DB=6.5

OpenStudy (kinggeorge):

Don't worry, still here, just have other things I must do as well. However, I'm not getting 6.5 as the length for DB.

OpenStudy (anonymous):

7+6.5=13.5

OpenStudy (kinggeorge):

You have that BC=13 and DC=\(7\sqrt3\). Using the pythagorean theorem, what should DB be?

OpenStudy (anonymous):

wait

OpenStudy (anonymous):

By using the reflexive property, angle C=C

OpenStudy (anonymous):

By using the reflexive property, angle D=D

OpenStudy (kinggeorge):

Don't even both with that stuff.

OpenStudy (anonymous):

and the other angle is 60 degrees

OpenStudy (anonymous):

so they are both 30-60-90 right triangles indefinitely

OpenStudy (anonymous):

SO DB is 6.5 because it s x

OpenStudy (anonymous):

DC is 6.5 and the square root of 3

OpenStudy (anonymous):

but DB is 6.5

OpenStudy (kinggeorge):

One, \(\Delta\)BCD is not actually a 30-60-90 triangle. Two, you're making this far more complicated than it should be. Just use the pythagorean theorem.

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

k

OpenStudy (anonymous):

13 squared= 169

OpenStudy (anonymous):

ehh

OpenStudy (anonymous):

AD equals 7

OpenStudy (anonymous):

DC equals 7 and the square root of 3

OpenStudy (anonymous):

so now what?

OpenStudy (anonymous):

what numbers should I plug in for Pythagorean Theorem>

OpenStudy (kinggeorge):

Let \(13=c\), \(7\sqrt3=b\), and solve for \(a\) in \[\sqrt{a^2+b^2}=c\]

OpenStudy (anonymous):

ok...

OpenStudy (anonymous):

because 7 and the square root of 3 share sides, right?

OpenStudy (anonymous):

reflexive property of DC?

OpenStudy (kinggeorge):

Because the length of DC is \(7\sqrt3\), and the length of the hypotenuse of \(\Delta\)BCD is 13. And because DC is a leg of that triangle.

OpenStudy (anonymous):

kkk

OpenStudy (anonymous):

like I said, reflexive property DC

OpenStudy (anonymous):

so DB=4.69041576

OpenStudy (anonymous):

so the answer is approximately 11.7

OpenStudy (anonymous):

right?

OpenStudy (kinggeorge):

Looks right to me.

OpenStudy (anonymous):

yeh!!!!!!!!!!!!!!!!!!!!!!

OpenStudy (anonymous):

I got quite a few more problems coming uo

OpenStudy (anonymous):

Ready for a bunch of medals?

OpenStudy (anonymous):

k

OpenStudy (kinggeorge):

Bring it on :P

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