Look at the figure shown below.
What is the length of Segment AB to the nearest tenth of a meter?
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OpenStudy (anonymous):
OpenStudy (anonymous):
this problem is not multiple choice; tips?
OpenStudy (kinggeorge):
Since \(\Delta \)ADC is a 30-60-90 triangle, you can find the lengths of AD and DC easily. Using the length of DC, and BC, you can use pythagorean theorem to get the length of DB.
Length DB+AD =AB
OpenStudy (anonymous):
k
OpenStudy (anonymous):
ehh
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OpenStudy (anonymous):
AD equals 8.082903769
OpenStudy (anonymous):
Side AB is 16.16580754
OpenStudy (anonymous):
Am I right so far?
OpenStudy (anonymous):
ahhh
OpenStudy (kinggeorge):
Give me minute
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OpenStudy (anonymous):
there's a shortcut to 30-60-90 right triangles
OpenStudy (anonymous):
AD equals 7
OpenStudy (anonymous):
and DC equals 7 and the square root of 3
OpenStudy (anonymous):
and there you have it
OpenStudy (anonymous):
am I right?
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OpenStudy (kinggeorge):
So far that looks right. What do you get for DB?
OpenStudy (anonymous):
well...
OpenStudy (anonymous):
I don't know if triangle CDB is a right triangle :(
OpenStudy (anonymous):
I think it is...
OpenStudy (anonymous):
IF so, angle C=30...
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OpenStudy (anonymous):
Wait...
OpenStudy (anonymous):
Reflexive property of equality!!!!!!!!!!!!!!!
OpenStudy (anonymous):
Angle D=angle D
OpenStudy (anonymous):
so angle D=90 degrees
OpenStudy (anonymous):
Angle C=30
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OpenStudy (anonymous):
And angle B=60 degrees
OpenStudy (anonymous):
so DB equals 6.5
OpenStudy (anonymous):
and DC equals 11.25833025
OpenStudy (anonymous):
so AB equals 7+6.5=13.5!!!!!!!!!!!
OpenStudy (anonymous):
AD=7 while DB=6.5
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OpenStudy (kinggeorge):
Don't worry, still here, just have other things I must do as well.
However, I'm not getting 6.5 as the length for DB.
OpenStudy (anonymous):
7+6.5=13.5
OpenStudy (kinggeorge):
You have that BC=13 and DC=\(7\sqrt3\). Using the pythagorean theorem, what should DB be?
OpenStudy (anonymous):
wait
OpenStudy (anonymous):
By using the reflexive property, angle C=C
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OpenStudy (anonymous):
By using the reflexive property, angle D=D
OpenStudy (kinggeorge):
Don't even both with that stuff.
OpenStudy (anonymous):
and the other angle is 60 degrees
OpenStudy (anonymous):
so they are both 30-60-90 right triangles indefinitely
OpenStudy (anonymous):
SO DB is 6.5 because it s x
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OpenStudy (anonymous):
DC is 6.5 and the square root of 3
OpenStudy (anonymous):
but DB is 6.5
OpenStudy (kinggeorge):
One, \(\Delta\)BCD is not actually a 30-60-90 triangle.
Two, you're making this far more complicated than it should be. Just use the pythagorean theorem.
OpenStudy (anonymous):
right?
OpenStudy (anonymous):
k
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OpenStudy (anonymous):
13 squared= 169
OpenStudy (anonymous):
ehh
OpenStudy (anonymous):
AD equals 7
OpenStudy (anonymous):
DC equals 7 and the square root of 3
OpenStudy (anonymous):
so now what?
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OpenStudy (anonymous):
what numbers should I plug in for Pythagorean Theorem>
OpenStudy (kinggeorge):
Let \(13=c\), \(7\sqrt3=b\), and solve for \(a\) in \[\sqrt{a^2+b^2}=c\]
OpenStudy (anonymous):
ok...
OpenStudy (anonymous):
because 7 and the square root of 3 share sides, right?
OpenStudy (anonymous):
reflexive property of DC?
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OpenStudy (kinggeorge):
Because the length of DC is \(7\sqrt3\), and the length of the hypotenuse of \(\Delta\)BCD is 13. And because DC is a leg of that triangle.
OpenStudy (anonymous):
kkk
OpenStudy (anonymous):
like I said, reflexive property DC
OpenStudy (anonymous):
so DB=4.69041576
OpenStudy (anonymous):
so the answer is approximately 11.7
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OpenStudy (anonymous):
right?
OpenStudy (kinggeorge):
Looks right to me.
OpenStudy (anonymous):
yeh!!!!!!!!!!!!!!!!!!!!!!
OpenStudy (anonymous):
I got quite a few more problems coming uo
OpenStudy (anonymous):
Ready for a bunch of medals?
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