simplify e^(1+ln(x))

Question

anonymous · Answer

use the law on exponents e^(a + b) = e^a * e^b
then use then use the law on logarithms e^(ln c) = c

anonymous · Answer

HOW?

anonymous · Answer

$$e^{a+b} = e^a.e^b$$

$$e^{lnx} = x$$

Use the above formulae you will get your answer...

anonymous · Answer

WOULD you please elaborate more

anonymous · Answer

What is there in place of a??

anonymous · Answer

i dont know

anonymous · Answer

See,

Compare:

$$e^{1 + lnx} = e^{a + b}$$

Now compare it and tell me what is there in place of a?

anonymous · Answer

1

anonymous · Answer

Yes..
And in place of b?

anonymous · Answer

lnx

anonymous · Answer

Yes..

$$e^{a+b}= e^a.e^b$$

Apply this formula and you know a = 1 and b= lnx

anonymous · Answer

i dont get it on how to do. would you plese solve it for me?

anonymous · Answer

Why??
Where are you facing problem..
See when the bases are same their exponents if in sum can be brought to multiplication as that formula is saying...

anonymous · Answer

I DONT see the connection to my question

anonymous · Answer

$$e^{1 + lnx} = e^1.e^{lnx}$$

What is the problem you are facing in doing this??

anonymous · Answer

once you have e^1 x e^(lnx) do you leave it as is or do the bases cancel?

anonymous · Answer

And you know now:
$$e^{lnx} = x$$

anonymous · Answer

Oh okay. I can see it now. Sorry the other girl was so rude. Thanks so much!