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Mathematics 21 Online
OpenStudy (anonymous):

The sum of the number of edges and vertices of the polyhedron is ________.

OpenStudy (anonymous):

Look at the net of the given polyhedron.

OpenStudy (anonymous):

OpenStudy (anonymous):

tips?

OpenStudy (kinggeorge):

Start counting :P

OpenStudy (anonymous):

it has 8 faces

OpenStudy (anonymous):

since it seems to be a prism, it should have 24 edgess

OpenStudy (kinggeorge):

Oh wait, those fold together. It's not quite as simple as I thought it would be.

OpenStudy (anonymous):

so is it a pyramid?

OpenStudy (anonymous):

if so, the edges equal 16

OpenStudy (kinggeorge):

I'm not sure what exactly you would call the shape, but I will tell you there are fewer than 16 edges.

OpenStudy (kinggeorge):

For now, only look at the triangle at the top and bottom of the diagram. These both have 3 edges, and they won't have any sharing edges.

OpenStudy (anonymous):

k

OpenStudy (kinggeorge):

However, the they will share some edges with the row of triangles in the middle. In particular, they will share the all of the edges on the top and bottom of that row.

OpenStudy (anonymous):

k

OpenStudy (kinggeorge):

That means we have 6 edges so far, and we've already counted the edges on the top.bottom triangle, and all the edges on the top/bottom of the row of triangles. The only edges we have left to count are those drawn diagonally in the middle row of triangles.

OpenStudy (anonymous):

k

OpenStudy (kinggeorge):

There are 7 edges there. However, the outer edge will be shared, so we subtract 1. This gives us \(6+6=12\) edges.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

how about vertices?

OpenStudy (kinggeorge):

Give me a minute more to make sure, but I think it would just be 6 vertices.

OpenStudy (anonymous):

12+6=18

OpenStudy (anonymous):

wait

OpenStudy (anonymous):

use Euler's formla

OpenStudy (anonymous):

8+6-2=12

OpenStudy (anonymous):

Euler's formula is Faces plus vertices minus edges=2

OpenStudy (anonymous):

so you are right

OpenStudy (kinggeorge):

I believe, when you fold this up you will get an octahedron. So if you need more confirmation, just look at the handy dandy picture here http://en.wikipedia.org/wiki/Octahedron And Euler's formula is a much better approach than just counting.

OpenStudy (anonymous):

k

OpenStudy (anonymous):

ty

OpenStudy (kinggeorge):

you're welcome.

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