Find the distance between the points given: (2, 2) and (5, 5) A. 3 B. 3 rad 2 C. 7 rad 2
Lets use the distant between two points formula. \[d = \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}\] now (2,2) and (5,5) x1,y1 x2,y2 so try to substitute those values into the formula and you should get a value and that is your answer.
attempt to do it yourself and I will tell u if u achieve the right answer.
i did but well i got \[\sqrt{50}\] nd wen i reduced it i got 7.07... , but none of those are there 0.o
\[Distance = \sqrt{(y_2 - y_1)^2 + (x_2 - x_1)^2}\]
\[D = \sqrt{(5 - 2)^2 + (5-2)^2} = \sqrt{9 + 9}\] Can you solve now??
ohh crapp i was doing da wrong problem over here lol hold up
Do you know how to solve \[\sqrt{18}\] ??
\[\sqrt{((5-2)^2+(5-2)^2}\] \[=3\sqrt{2}\]
@JayDS let felly solve this on her own..
If you can use the calculator you can just type it in.
yep I know, I was doing that but you butted in.
That does not mean that you will solve it on your own...
how is it \[\sqrt[3]{2}\] tho?? bcus \[\sqrt{18}\] reduces to 4.24....
Firstly make the factors of 18... Can you do that??
yeahh
What are the factors that makes 18???
1,2,3,6,9,18
Yes, now from these 18 can be made from which numbers??
what do you mean?
See 20 has factors: 1, 2 , 4, 5, 10 So, from these numbers I want to form 20.. How can I get that?? 20 = 4*5 Or 20 = 2*2*5 Getting my point?? If yes, then what are the factors that 18 comprises of??
oh, 1*18, 2*9, 3*6, 6*3, 9*2
See you said: 18 = 2*9 or 9*2 I say 18 = 3*3*2 Am I right?? You can use the factors twice and thrice also.. Getting?
oooohh, ii get it now! thank youu !!! :)
Okay welcome dear...
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