find the domain of f(x)^-1 if f(x)=4x-8 ?

Question

mertsj · Answer

f(x)=4x-8 is a line.  Its inverse is also a line and thus the domain of both is all real numbers.

anonymous · Answer

thank you!!!

anonymous · Answer

No it isnt, be careful. 4x-8 is a line. But its inverse is $${1 \over 4x-8}$$
If the denominator becomes 0, the function explodes. You cant divide by zero.
So in other words, 4x-8=0 may NOT happen.
Solving for x: 4x = 8, x=2
So the domain is all the real numbers EXCEPT 2

mertsj · Answer

@soati
$$y=4x-8$$
Inverse is: 
$$x=4y-8$$
$$x+8=4y$$
$$y=\frac{1}{4}x+2=f ^{-1}(x)$$

mertsj · Answer

@soati 
A function and its inverse are symmetrical about the line y = x.  Thus the inverse of a line is a line.

mertsj · Answer

@noniebug 
yw

mertsj · Answer

@soati You have written the reciprocal of the function, not the inverse.  Perhaps you do not know the difference.

anonymous · Answer

lol really. I do.
He wrote f(x)^-1 rather than f^-1(x). Thats a huge difference.
$$f(x)^{-1} = 1/ f(x)$$
$$f^{-1}(x)$$ is what he wanted.

mertsj · Answer

@soati But what you wrote was that the INVERSE is 
$$\frac{1}{4x-8}$$

anonymous · Answer

He said f(x)^1, so i was correct.

it doesnt matter what i said. the maths are correct.
not sure why youre holding on to this.

mertsj · Answer

@soati

Because you contradicted a true statement with a false one and you're still insisting that your false statement is true: " No it isnt, be careful. 4x-8 is a line. But its inverse is 1/ 4x−8"  So who is holding on to what?

anonymous · Answer

holy crap. you either like the conflict or youre just retarded.

wont be feeding your trolling anymore.