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Mathematics 10 Online
OpenStudy (anonymous):

Solve the matrix equation

OpenStudy (anonymous):

OpenStudy (foolaroundmath):

AX = C Matrix A has form 2 x 2 C has form 2 x 2 So, The matrix X must have the form 2 x 2. Let \[X = \begin{bmatrix} a & b\\ c & d \end{bmatrix}\]. If we multiply \[\begin{bmatrix} -7 & -3\\ 2 & 1 \end{bmatrix}* \begin{bmatrix} a & b\\ c & d \end{bmatrix} = \begin{bmatrix} -7a-3c & -7b-3d\\ 2a+c & 2b+d \end{bmatrix}\] \[ \begin{bmatrix} -7a-3c & -7b-3d\\ 2a+c & 2b+d \end{bmatrix} = \begin{bmatrix} 2 & 6\\ 6 & 9 \end{bmatrix}\] Equating the terms on LHS with corresponding terms on RHS, -7a - 3c = 2 -7b - 3d = 6 2a + c = 6 2b + d = 9 Solve these two systems of equations

OpenStudy (anonymous):

Wow thats alot ok thanks

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