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Mathematics 20 Online
OpenStudy (anonymous):

What is the equation of the following graph

OpenStudy (anonymous):

OpenStudy (anonymous):

That is an ellipse. It depends on what you want to call your major axis and what you want to call your minor axis but in the end you'll still get the same thing when you simplify. For a > b: \[\large\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\] http://www.mathwarehouse.com/ellipse/equation-of-ellipse.php

OpenStudy (anonymous):

The only trick here is that you need to choose your a & b (major & minor axes) wisely. In this case it's very obvious that it's stretched out horizontally.

OpenStudy (anonymous):

@agentx5 how do i determine the numbers?? i dont get that

OpenStudy (anonymous):

Solving for Y: \[y=\pm b\sqrt{1-(\frac{x}{a}})^2 \] If you have like a TI-84 graphing calculator you can now graph this and see You're have to enter as two almost-identical equations, one positive, one negative: \[y= (2) \sqrt{1-(\frac{x}{9}})^2 \] \[y= -(2) \sqrt{1-(\frac{x}{9}})^2 \]

OpenStudy (anonymous):

See what you get ;-)

OpenStudy (anonymous):

Remember, your major axis is from the center to the furthest two points, the largest diameter possible if you will. The minor axis is he shortest diameter possible (again must go through the center). The center for you here in this problem is exactly on the origin. That was nice of them. If they wanted to make it harder they could have made it not centered or partly rotated/turned the ellipse. ;-)

OpenStudy (anonymous):

@4everjames Have you graphed those yet?

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