Question

Can someone please explain this formula step by step to me? H(t) = -16t2 + vt + s

Answer 1

(acceleration)(time\(^2\)) + (velocity)(time) + (initial displacement)



Velocity is in units/time.
Acceleration is in units\(^2\)/time



So for example, with a velocity in units like m/s (meters per second):

Position as a function of time in meters = (___ m/s\(^2\))(___ s)\(^2\) + (___ m/s)(___ s) + (___ m)

Answer 2

You input a time, you get a position answer in meters.

Answer 3

f(input)=output f(x)=y This is the very definition of a function.

Answer 4

H(t)= -16t^(2) + (165)t + (110)

This is what I need help explaining

Answer 5

and solving...

Answer 6

-16 units/second\(^2\) = acceleration
165 units/second = velocity magnitude
110 units = initial position/displacement

You need H(t) = something or H(something) = ? in order to "solve" anything here

Answer 7

It's either a "What's the time when it's at here?" type of question, or a "When it's at this time, where is it?" type of question.

Answer 8

I can't be any more explicit than that

Answer 9

A firecracker shoots up from a hill 165 feet high with an initial speed of 110 feet per second. Using the formula H(t) = -16t2 + vt + s, determine how long it will take the firecracker to hit the ground.


7.2 seconds

7.5 seconds

7.8 seconds

8.1 seconds

Answer 10

H(t) = ((-16) ft/s\(^2\))((t) s)\(^2\) + ((110) ft/s)((t) s) + (165 ft) = 0 ft
or
H(t) = ((-16) ft/s\(^2\))((t) s)\(^2\) + ((110) ft/s)((t) s) + (165 ft) = 165 ft

Solve them and see which is the answer they're looking for. Units feet (ft) and seconds (s) will cancel until you get your answer just seconds. You're solving for t.