Indicate in standard form the equation of the line passing through the given points. S(, 1), T(, 4)
S(1/2,1) T(1/2,4)
Its asking for just X, not x+y and therefore I'm lost/frustrated.
direction vector is vertical, for examle (1,0) so: x-1/2 =0 x=1/2
Okay could you explain that a wee bit more? I'm still lost ..
in a standart form ax+by=c (a,b) is a vector which is perpendicular to the line. Since the line you whant is vertical, perpendicular vector could be (1,0). Rest just plug some point in to the equation...
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but what about y? its ax+by=c Ugh...
y coordinate of the vector is 0. Remmeber our perpendicular vector is (1,0), so 1(x-p)+0*(y-q)=0 x-p=0
So for my equation what would it be?? I hate this I dont get what numbers go where or what the entire thing even means.
equation is x=1/2
ok?
How'd you get that though.....
I'm sorry I'm not trying to be thick...
like i said befor: in a standart form ax+by=c (a,b) is a vector which is perpendicular to the line. Since the line you whant is vertical, perpendicular vector could be (1,0).So when i substitute this in the equation ax+by=c I get: 1x+0*y=c, or x=c
@natnatwebb
thank you for your help.
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