Question

A boat sets out from the north shore of a 200 m wide east-flowing river. The boat always faces due south but the current carries it
300 m downstream while crossing. The trip takes 2.0 min. Assume three significant digits.
(a) What is the boat's displacement during the trip?
(b) What is the boat's average velocity during the trip?
(c) If the boat's velocity relative to the water is 1.7 m/s [S], what is the velocity of the current?

Answer 1

a.) this is basic vector component triangle where vertical is 200 and horizonal is 300.. Find the Hypot.
Should be something like: square root of 200^2 + 300^2
Got 360.555 or 361 meters.

b.) it traveled 361 meters in 2 mins
So some conversions:
(361m / 2min) * (1min / 60sec)
This gives you: 3.008333333 meters/sec
or 3.01 m/s

c.) should be the difference of the vector component in the horizonal direction.
Remember there river flows east so there will be no current in the south direction.
3.01 - 1.7 = 1.31 in the east direction.

Good Luck. Hope this is good for you.

Answer 2

thank you