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Separable equations \[\frac{dy}{dx}=\frac{ycosx}{1+y^{2}}\] \[\int \frac{1+y^{2}}{y}dy= \int cosx dx\] \[\int \frac{1+y^{2}}{y}dy= sinx +C\]
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u=1+y^2 ?
simplify the integrand on the left side by doing long division first....
ok
y+ 1/y
\[\huge \frac{1+y^2}{y}=\frac{1}{y}+\frac{y^2}{y}=y^{-1}+y \]
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yep... that's easily integrated huh?
yep y^2 /2
what about y^-1 ?
1+ y^2 /2
1+ (y^2)/2
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wait...
\[\large \int \frac{1}{y}dy=lny+C \]
duh...thanks
lolz
yw...:)
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