OpenStudy (rayford):

Select the graph of y = – |x + 3| + 2

5 years ago
hero (hero):

It will look something like this: |dw:1340928200271:dw|

5 years ago
hero (hero):

But that's just a hint.

5 years ago
hero (hero):

not the actual graph

5 years ago
OpenStudy (rayford):

may you give me another hint? possibly another coordinate?.

5 years ago
hero (hero):

As far as a hint goes, I've given you plenty. The only thing you need to figure out is the point where the actual vertex of the graph lies

5 years ago
OpenStudy (rayford):

but isn't the vertex 2?

5 years ago
OpenStudy (anonymous):

nope..

5 years ago
OpenStudy (anonymous):

The vertex is a coordinate with both an x-value and y-value. Right now, you have (x, 2). You have to figure out what x is.

5 years ago
OpenStudy (alexwee123):

think of it this way this is a absolute value graph that is transformed it is reflected over the x axis, translated 3 left and 2 up so think of the vertex of a normal absolute function which is (0,0) then apply those transformations onto it

5 years ago
OpenStudy (anonymous):

Plug in what you have for y to solve for x. y = -|x + 3| + 2 2 = -|x + 3| + 2 Solve for x. You should also notice a pattern. The two is a part of the vertex because it says plug 2. However, for horizontal shift, you do something with the x + 3 to get the x-value of the vertex.

5 years ago
OpenStudy (rayford):

thank you everyone i understand how easy this is lol. thank you very much.

5 years ago