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OpenStudy (anonymous):
If a*b= a^2-b^2/a+b, what is 3*2.
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OpenStudy (anonymous):
-5
-2
1
2
5
OpenStudy (anonymous):
I got 1
OpenStudy (jamesj):
So this expression is defining a new operation: *
a*b is defined to be (a^2 - b^2)/(a+b)
is that the right placement of brackets?
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
Is my answer 1, right?
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OpenStudy (jamesj):
Well, notice that
\[ a^2 - b^2 = (a-b)(a+b) \]
Hence
\[ \frac{a^2-b^2}{a+b} = \frac{(a+b)(a-b)}{a+b} = a-b \]
Thus
3*2 = 3 - 2 = 1,
which is what you wrote above.
OpenStudy (anonymous):
So when you get problems like this, you are basically plugging in the values into where the c and f notations?
OpenStudy (anonymous):
like you plug in the numbers where they are supposed to go? its that easy?
OpenStudy (jamesj):
Yes. But it's worth looking at the expression to see if you can simplify it first, as I did above.
OpenStudy (anonymous):
Do u mind looking at this one?
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OpenStudy (jamesj):
post as a new question if you don't mind.
OpenStudy (anonymous):
Let r (triangle) s=rs + s for all integers r and s. What is the value of 4 (triangle) 5?
OpenStudy (anonymous):
@JamesJ
OpenStudy (anonymous):
options:
18
20
24
25
40
OpenStudy (jamesj):
what do you think it is?
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OpenStudy (anonymous):
I got 25:)?
OpenStudy (jamesj):
yes
OpenStudy (anonymous):
ok cool
OpenStudy (anonymous):
I'll post more if I have to in a sec!
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