If a*b= a^2-b^2/a+b, what is 3*2.
-5 -2 1 2 5
I got 1
So this expression is defining a new operation: * a*b is defined to be (a^2 - b^2)/(a+b) is that the right placement of brackets?
Yes
Is my answer 1, right?
Well, notice that \[ a^2 - b^2 = (a-b)(a+b) \] Hence \[ \frac{a^2-b^2}{a+b} = \frac{(a+b)(a-b)}{a+b} = a-b \] Thus 3*2 = 3 - 2 = 1, which is what you wrote above.
So when you get problems like this, you are basically plugging in the values into where the c and f notations?
like you plug in the numbers where they are supposed to go? its that easy?
Yes. But it's worth looking at the expression to see if you can simplify it first, as I did above.
Do u mind looking at this one?
post as a new question if you don't mind.
Let r (triangle) s=rs + s for all integers r and s. What is the value of 4 (triangle) 5?
@JamesJ
options: 18 20 24 25 40
what do you think it is?
I got 25:)?
yes
ok cool
I'll post more if I have to in a sec!
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