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Simplify. square root of 6 (square root of 33 + 7)
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Is this your question:\[\sqrt{6}(\sqrt{33}+7)\]
yes
Just distribute root(6) to the brackets..
when two terms are raised to the same root you are able to multiply whatever is under the square root: \[\sqrt{a}\sqrt{b}=\sqrt{ab}\]
So, this now becomes \[\sqrt{6*33}+7\sqrt{6}\]\[\sqrt{198}+7\sqrt{6}\]
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\[\sqrt{22*9}+7\sqrt{6}\] \[\sqrt{22}*\sqrt{9}+7\sqrt{6}\] \[3\sqrt{22}+7\sqrt{6}\]
Do you understand @tngirl865
yes I do.. thank u very much for helping me!
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