Question

anyone ? help please ?

Answer 1

with what exactly?

Answer 2

The graph of which quadratic equation is shown below?

Answer 3

What is the vertex?

Answer 4

i dont knoww

Answer 5

The vertex is the tip of the parabola so it is (1,9) (h,k) and putting what we have so far into the vertex equation \[y=a(x-h)^2+k\]\[y=a(x-1)^2+9\] and now you just find a point on the graph substitute it for x and y and solve for a and then fill in the vertex equation.

Answer 6

i still dont get it

Answer 7

You don't get what I said... or what to do next?

Answer 8

what to do next

Answer 9

Okay, so let's look at your beautiful graph given find me a point on the graph (any one)

Answer 10

8

Answer 11

with x and y coordinate (x,y)

Answer 12

i ahve no diea how to do this nto be honest.

Answer 13

do you know any calculus?, if you do diffrentiate and find the required maximum..

Answer 14

no im sorry i dontt

Answer 15

i reallly needdd help on this please you guys

Answer 16

we dont even know what the question is.

Answer 17

actually nvm, solving it now

Answer 18

He has to find the equation for the graph @Posideon

Answer 19

ok this is how you do it. y=(x-k)^2 + c is the standard equation for a parabola. as this parabola is upside down im gonna use y=-(x-k)^2 +c. k represents the shift horizontally. it has been moved left 2 and up 9 so the equation is y=-(x-2)^2 + 9. im assuming it hasnt been expanded(made fatter or anything as i cbf solving that). Enjoy.

Answer 20

the vertex is not (2,9) it's (1,9) @Posideon

Answer 21

ah my bad. change the 2 to a 1. its actually at (-1,9)

Answer 22

Oh yeah, haha