Question

Circle A has an equation of (x + 8)^2 + y^2 = 16. Where is the center of the circle located?

Answer 1

These are the answer choices:
on the x-axis
on the y-axis
in the first quadrant
in the third quadrant

Answer 2

\[(x-a)^{2}+(y-b)^{2}=r^{2}\]
be a circle......
then center is (a,b)

in you case\[(x-(-8))^{2}+(y-0)^{2}=16\]

Answer 3

so center is (-8,0)

Answer 4

THE_PROPHET is absolutely correct !

Answer 5

answer is on the x-axis:)