Question

find the derivative using the product rule and the chain rule:

(x²+1)(x²+2)^¼

Answer 1

uv'+vu'

Answer 2

where do you get confused?

Answer 3

\[\frac{dy}{dx}=\frac{dy}{du}\frac{du}{dx}\]

Answer 4

finding the derivative of (x²+1)

Answer 5

where u is your inner function

Answer 6

\[\frac{d}{dx}[x^n]=nx^{n-1}\]

Answer 7

i know.. so it's just 1?

Answer 8

x^n where your n is 2 in this case

Answer 9

\[\frac{d}{dx}[k]=0\] where k is any constant

Answer 10

I mean when you do the vu' part ... is it just (x²+2)^¼ (1)

Answer 11

no since the derivative of x^2 = 2x

Answer 12

because using the chain rule.. (x²+1) = 1 ... but the inside is 2x

Answer 13

no need to d the chain rule for that

Answer 14

why not?

Answer 15

the chain function is when you have an outer and inner function

Answer 16

OH! Ok thank you so much!

Answer 17

such as

\[ln(x^2+2)\]
or
\[(x^2+2)^2\]

Answer 18

Yes I understand. Thank you so much.

Answer 19

so whe you figure the answer out , post it