Question

http://media01.switchedononline.com/g_alg01_2011/13/img_test_problem86.gif

Answer 1

\[\huge \frac{\frac{y}{4} + 1}{\frac{y^2}{16} - 1} \implies \frac{\frac{y + 4}{4}}{\frac{y^2 - 16}{16}}\]
do you get that part?

Answer 2

yes

Answer 3

good..
\[\huge \frac{\frac{y+4}{4}}{\frac{(y+4)(y-4)}{16}}\]
do you get that?

Answer 4

Yes

Answer 5

so if you get it..then you know what the next step will be ;)

Answer 6

1/y-4?

Answer 7

what did you do?

Answer 8

The y+4 cancel. then 16 goes into 4?

Answer 9

\[\huge \frac{\frac{\cancel{y+4}}{\cancel 4}}{\frac{\cancel{(y+4)}(y-4)}{\cancel{16} 4}}\]
so the answer becomes \[\huge \frac{1}{\frac{y-4}{4}} = \frac{4}{y-4}\]

Answer 10

Thanks. i didnt finish simplifying

Answer 11

\[\Huge \color{maroon}{\mathtt{\text{<tips hat>}}}\]