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find the reminder when x51+51 is divided by (x+1)
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You mean \(x^{51}+51\) divided by \(x+1\), right?
Aha.. the remainder theorem. \( \color{Black}{\Rightarrow f(x) = x^{51} + 51 }\) This is being divided by \(x - (-1)\) Plug in -1 for x in f(x)
\( \color{Black}{\Rightarrow (-1)^{51} + 51}\) ^ remainder would be this
The odd powers of -1 are always -1. \( \color{Black}{\Rightarrow -1 + 51}\) \( \color{Black}{\Rightarrow 50}\) Therefore, remainder is 50.
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