Ask your own question, for FREE!
Physics 14 Online
OpenStudy (anonymous):

Any questions on military physics?

OpenStudy (anonymous):

ya what is military physics?

OpenStudy (anonymous):

Dear @shayanreloaded, Military physics is the physics behind the machines of war that we employ to win a battle. It can be anything from artillery, to aircrafts. With regards, @Arnab_Chatterjee

OpenStudy (anonymous):

k

OpenStudy (anonymous):

?

OpenStudy (anonymous):

What is the pitch?

OpenStudy (anonymous):

If simply said, pitch is the angle by which the elevator is hinged upward or downward.

OpenStudy (anonymous):

hey i think this problem is similar to the cyclist executing a loop....u have to equate the kinetic and potential energies and do it..i have the expressions in my text book..am i rit arnab?

OpenStudy (anonymous):

Way different.....a cyclist is cycling on a planar surface. Where here, we need to find out the airflow, the lift, the angle of attack and pitch...

OpenStudy (anonymous):

so how will u do it now?

OpenStudy (anonymous):

I told him to supply the pitch...

OpenStudy (anonymous):

Lift is an unit of force, not length..

OpenStudy (anonymous):

My friend..then the aircraft designers must leave their jobs..... 56 N is impossible to keep an aircraft flying which weighs at least 5000 kgs. that too at 720 km/hr.

OpenStudy (anonymous):

A military column of trucks, L, is 28.0 km long. Coincidentally, it is driving west at a constant 28.0 km/hr. The commanding general, in truck G, is at the head of the column. At the moment truck G reaches the border line of the combat zone, the communication officer in truck C at the very back end of the column pulls out with a message for the general. Truck C drives west alongside the column at a constant velocity, V. Later, at a time, t, truck C reaches G. Truck C immediately turns around and drives back toward the rear. He reaches the end exactly 1.00 hour after he started his drive to the front. What was the constant velocity, V, of Truck C?

OpenStudy (anonymous):

I got the answer it is 67.59797975 km/hr.

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

I used my calculator...

OpenStudy (anonymous):

what is the stroboscopic effect?

OpenStudy (anonymous):

i saw in a video that it can be demonstrated with a flight's jet engine's fan(what is that name?)

OpenStudy (anonymous):

The Stroboscopic Effect is the effect caused by aliasing when you view a constant motion in quick short flashes or series. And it is called a Turbofan.

OpenStudy (anonymous):

i got a problem in classical physics can i ask?

OpenStudy (anonymous):

@Arnab_Chatterjee can i ask?

OpenStudy (anonymous):

its a problem on work energy theorem

OpenStudy (anonymous):

Go on...

OpenStudy (anonymous):

physical example of storoboscopic effect is when voltage goes down and your tube light starts flickering rapidly you look on fan and you can see its wings appearing stationary for a while.

OpenStudy (anonymous):

if i am not wrong :P

OpenStudy (anonymous):

IF no external force act(or the work done by them is 0) and the internal forces are conservative, the mechanical energy remains constant. BUT if u consider two charges 1 positive other negative they both attract each other, when we consider them as a system their attraction forces become internal and since force is internal the energy should remain constant which means no work is done but how is this possible since the objects have moved some distance that two with force applied on them

OpenStudy (anonymous):

Correct example @theyatin

OpenStudy (anonymous):

@Arnab_Chatterjee help please

OpenStudy (anonymous):

i didn't get what you want to know?

OpenStudy (anonymous):

Dear @Rdx , Please wait a bit..I have an urgent call.

OpenStudy (anonymous):

I have your answer.

OpenStudy (anonymous):

@theyatin well i m saying if internal force work then how can energy be constant

OpenStudy (anonymous):

well i don't know. . . :D

OpenStudy (anonymous):

When charges attract each other, they move towards each other due to the force of ionic attraction. At that time they act as separate ions and like in a Electrolytic Experiment, they move towards each other, although their energy is internal. It is the difference of charges that locomotates them. Thus they move some distance without any force applied on them.

OpenStudy (anonymous):

So, what do you say @Rdx ?

OpenStudy (anonymous):

umm 1 sec

OpenStudy (anonymous):

well now i see the whole picture. total energy is constant because it is a isolated system what ever happens inside the whole energy would be constant. . . where ever the charges move what ever speed would be

OpenStudy (anonymous):

@Arnab_Chatterjee they move becaus of their mutual force of attraction if they move in a smallest distance without ant force they violate newtons laws

OpenStudy (anonymous):

They have a force of attraction...which as I mentioned is the force of ionic attraction due to variation in charges. (Similar principle is used in Static Electricity)

OpenStudy (anonymous):

well do newtons laws are applicable on weak forces?? i dont tknow if it is

OpenStudy (anonymous):

Sure, they are.

OpenStudy (anonymous):

ok thanx. . .

OpenStudy (anonymous):

so @Arnab_Chatterjee what u r saying is a direct contradiction to newtons laws

OpenStudy (anonymous):

If the charges move to each other the energy stays constant in the system, one wins what the other one loses. You can visualize it like vertical movement using potential energy

OpenStudy (anonymous):

finding Projectile or trajectory of a fired canon can become a good question on military physics.@Arnab_Chatterjee if find a good one please message me too.

OpenStudy (anonymous):

Ok. @devarsh.ruparelia

OpenStudy (anonymous):

range of a gun/ recoil /length of rifle/ mass of bullet many que may aris about many aspect :P

OpenStudy (anonymous):

Go on...@theyatin I can also explain the working.

OpenStudy (anonymous):

NAAAH I KNOW THIS STUFF DON'T NEED TO ASK . . I JUST GAVE OTHERS OPTIONS TO ASK QUE ABOUT. .. EXPLAIN SILENCER USED IN PISTOLS IF YOU CAN. . .

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!