Question

Can you find the fallacy in this mathematical proof that the product of two even integers results in an even integer?

Answer 1

Let \(a = 2k_1\) and \(b = 2k_2\) so that both a, b are even integers.
Therefore, \[ab = 2k_1 \cdot 2k_2 = 4k_1 k_2 = 2 (2k_1 k_2)\]

Which is also an even integer.

QED

Answer 2

lol that is KingGeorge's proof

Answer 3

??

Answer 4

there is no fallacy.:D

Answer 5

im sure there is -_- this is supposed to be impossible to prove :/

Answer 6

Look at my tutorial

Answer 7

http://openstudy.com/study#/updates/4fed7487e4b0bbec5cfccbfb

Answer 8

what am i looking for in there?

Answer 9

lol @KingGeorge you win. no one could find the fallacy in your solution :p you truly are a king <grovels>