Can you find the fallacy in this mathematical proof that the product of two even integers results in an even integer?

Question

lgbasallote · Answer

Let $a = 2k_1$ and $b = 2k_2$ so that both a, b are even integers. 
Therefore, $$ab = 2k_1 \cdot 2k_2 = 4k_1 k_2 = 2 (2k_1 k_2)$$ 

Which is also an even integer.

QED

parthkohli · Answer

lol that is KingGeorge's proof

lgbasallote · Answer

??

anonymous · Answer

there is no fallacy.:D

lgbasallote · Answer

im sure there is -_- this is supposed to be impossible to prove :/

parthkohli · Answer

Look at my tutorial

parthkohli · Answer

http://openstudy.com/study#/updates/4fed7487e4b0bbec5cfccbfb

lgbasallote · Answer

what am i looking for in there?

lgbasallote · Answer

lol @KingGeorge you win. no one could find the fallacy in your solution :p you truly are a king <grovels>