$$\int\frac{1}{ln(x+1)}
dx$$

Question

$$\int\frac{1}{ln(x+1)}
 dx$$

mimi_x3 · Answer

@wasiqss

wasiqss · Answer

lemme try

mimi_x3 · Answer

Hint: similar to your other one.

mimi_x3 · Answer

But this is apparently an integral which does not have a close form..

wasiqss · Answer

okay

wasiqss · Answer

ash dont solve its for me

ash2326 · Answer

mimi_x3 · Answer

wasiqss · Answer

mishoo it was easy ~~~ i did it

wasiqss · Answer

just apply by parts

mimi_x3 · Answer

by parts? please elaborate.

mimi_x3 · Answer

i thought the first step is a substitution..

wasiqss · Answer

yeh take 1 as first functio

wasiqss · Answer

$$x/{(\ln(x+1)} - \int\limits_{}^{}x^2 +x$$

mimi_x3 · Answer

how about $u= ln(x+1)$ => $e^{u}= x+1$

wasiqss · Answer

if it can be done easily why take substitution..

mimi_x3 · Answer

but this is an integral which does not have a closed form right?

wasiqss · Answer

i dont understand forms :P i just know how to solve the ugliest of integrals :P

mimi_x3 · Answer

lol, but look at the answer on wolfram..

wasiqss · Answer

i dont trust wolfram cause in two questions i pointed out its mistake and did what it cant do :P

mimi_x3 · Answer

lol are you sure that you're right though? :P

wasiqss · Answer

i can do better than wolfram :P

mimi_x3 · Answer

lol