a lotto ticket has 9 numbers. assuming you can pick from 0 to 9 in each slot, how many possible combinations of numbers are possible?
is the answer 999999999?
^that's nine 9s
0,1,2,3,4,5,6,7,8,9 makes ten numbers
uh-huh?
If it has each slot, then 10^9 is pretty well.
how do i show a solution?
Because there are 10 numbers in each slot and 9 digits - we multiply 10 to itself 9 times.
where do the factorials come in?
10 to itself 9 times will mean 10^9 - which just means 1 and then 9 zeros.
btw..your thingy sounds like probability? lol
Factorials come in when a digit will not repeat.
1/10^9 is the probability of the winning combination right?
Yeah.
is that a coincidence?
Because there is only one combination, and 10^9 combinations are possible, then you are correct by that 1/10^9
Did you understand? @lgbasallote
considering as i have a hanging question...
what's the relation between probability and combinations? why do they almost look the same?
Yeah they do. Sometimes you have to use both permutations/combinations and probability. Such type of study of math is called Combinatorics.
oh wow cool. to think i realized that by myself. i must be a genius!! lol just kidding =)))) this "combinatorics" sounds interesting -_-
lolol
wait....if im calling myself a genius...what does that make the 12 year old kid teaching me o.O preposterous! :p
! :P
you dont know how shameful it is in my part that a 12 year old kid knows a branch of mathematics that i dont o.O
Combinatorics is the probability where the Pascal's triangle is involved.
WAHHHH SHUSHHHH MIMI!!!! :p
You know the pascals triangle in the binomial theorem?
lol Pascal's triangle is totally related to Combinations
dont poison my peaceful mind T_T
im getting out of this post!!!
Hah dw combinatorics is easy.
No, combinations don't involve the pascals triangle. Combinatorics which is binomial probability involves the pascals triangle.
Probability of getting EXACTLY two heads out of 5 tosses is figured out thru combinatorics.
Binomial theorem is completely related to Combinations and Pascal's triangle. Correction ^
Hah leave it lgba doesn't care.. let's spam his notifs now ;0
I have studied this before. Combinations is when \(r\) terms taken out randomly from \(n\) terms, the number of possibile combinations is \[\frac{n!}{r!(n-r)!} \] And for Binomial Probability (combinatorics) in \(n\) trials there are only two outcomes for each trial.
"Binomial probability is the probability with the theory of the expansion of the binomial \(x+y^n\)
Actually combinatorics is nothing but the number of permutations over total number of possibilities.
\((x+y)^{n}\)*
No Parth.In Binomial probability all of the stages are identical and each stage has only two possible outcomes, conventionally called "success" and "failure", and not neccessarily equally likely.
P(Getting 2 heads in 5 tosses)= \({\Huge {\left ({5! \over3!} \right ) \over 2^5 } }\)
\( \color{Black}{\Rightarrow\Large {20 \over 32} = {5 \over 8} }\)
I don't think this is right :|
That does not look like binomial probability; however I am not sure. I am not good with probability. I am just telling you that Binomial probability involved the Pascals Triangle. I don't think that you're right; I think it is doable by the Probability Tree Diagram. I am not certain though.
Nah no one needs tree diagrams :p
Yes for Multi Stage experiements.
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