Question

the condition that the roots of px^2 - px + q = 0 are in the ratio p:q is?

Answer 1

The only way the roots of a quadratic function is 0 is that the vertex is at the origin, (0,0), x-intercept are at 0.

Therefore, this must be the simple parabola function, \(f(x)=x^2\)

Answer 2

Now you know what to do :)

Answer 3

no

Answer 4

Ok, \(f(x)=x^2\) is exactly the same thing as\(f(x)=1x^2+0x+0\), do you agree?

Answer 5

1 is p
0 is q

Ratio would be 1:0

:)

Got it?

Answer 6

The answer should be 2p + q =0

Answer 7

let roots be a and b
sum of roots = a+b = 1
and ab = q/p
or 1/ab = p/q
and you want a/b = p/q
so 1/ab = a/b
=> a=1 or -1 (assuming one of the roots is not 0 i.e. q not equals 0)
for a=1, b=0 => not possible
so a= -1 and b =2 --> req condition
i may be wrong somewhere though,,hmm
you may also that p/q should be -1/2

Answer 8

well I can think that u know that if alpha and beta are roots of the equation then now i have given u two equations slove