Question

One of the factors of 3p^5 – 12p^3 is:

p^4

p + 2

p^2 + 4

4

I can't seem to solve this one, so yes help would be appreciated :)

Answer 1

See, when you put p = 2,
Then you are getting Zero..

Answer 2

So, (p-2) is one of its factors..
Since it is not given in the choices,
So by Long division method,
divide given expression with (p-2)..

Answer 3

1. What you wrote it an expression, not an equation. You solve equations, not expressions.

2. Factor out a 3p\(^3\). Then see if it factors further. (hint: it does indeed)

Answer 4

K I get 3p^3(p^2-4p)

Answer 5

@waterineyes , that's not an equation, you can't just plug in p = 2 like it's a function. Sorry m8

Answer 6

(p^2-4)*

Answer 7

You're correct so far @Loujoelou ;-)

Answer 8

well almost

Answer 9

3p^3(p^2-4)

Answer 10

\[3p^3(p^2-4)\]

Answer 11

Does x\(^2\) - a\(^2\) look familiar to you now? ;-)

Answer 12

a = 2, a^2 = 4

Answer 13

You can factor a bit more

Answer 14

So, when you divide,
You have now factors:

\[(p-2)(3p^4 + 6p^3) = 3p^3.(p-2).(p+2) = 3p^3(p^2 - 4)\]

Answer 15

So, P + 2 is the factor..

Answer 16

@agentx5 I am doing it right..

Answer 17

By equation you mean that you will find for x but I am not doing for that I am using that to make its factors...

Answer 18

3p^3(p+2)(p-2) That's what I wrote, w/ (p+2) as answer but had to refresh OS cause froze on me.

Answer 19

Tyvm @agentx5 & @waterineyes

Answer 20

np m8

Answer 21

Welcome dear..