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MIT 18.01 Single Variable Calculus (OCW) 50 Online
OpenStudy (anonymous):

Learning Derivatives Can Anyone Help Me With The Explanation On How To Do It... Thank You Very Much...

OpenStudy (anonymous):

ya sure

OpenStudy (anonymous):

whats the problem

OpenStudy (anonymous):

Well, in general, to find the derivative of a function f(x) we take [f(x+h)-f(x)]/h as the limit of h goes to 0. What this means is that we are finding the "slope" of the function as we determine the rate of change by making h arbitrarily small. For example, the derivative of the function x^2 would be the limit as h goes to 0 of [(x+h)^2-x^2]/h. We cannot set h to its limit yet or we would get an undefined solution, so we perform the basic algebra on the problem. From [(x+h)^2-x^2]/h we get [x^2+2xh+h^2-x^2]/h, which in turn becomes 2xh +h^2/h. Factoring out an h from the numerator gives us [h(2x+h)]/h, the h gets cancelled and we get 2x+h. Remembering to apply the limit as h goes to 0 we get the derivative of x^2 is 2x.

OpenStudy (anonymous):

Sanguine.Brother, I wouldn't have the patience to write out the entire definition of the derivative. But thanks for writing it out!

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