Question

Simplify.

Answer 1

^3square root of 343 + 3/4 ^3 square root of -8

Answer 2

do you understand the problem? I am having difficulty in drawing it out

Answer 3

no but i am going to make a guess that the first part is \(\sqrt[3]{343}\)
is that right?

Answer 4

open the file below:
https://dl.dropbox.com/u/52240971/Screen%20shot%202012-06-29%20at%202.47.36%20PM.png

Answer 5

and maybe the second part is \(\frac{3}{4}\sqrt[3]{-8}\) ?

Answer 6

i got an error

Answer 7

correct ... + 3/4

Answer 8

multiple choices:
1. 5 1/2
2. 8 1/2
3. -8 1/2
4. -5 1/2

Answer 9

ok then
\[\sqrt[3]{-8}=-2\] because \((-2)^3=-8\) and
\[\sqrt[3]{343}=7\]because \(7^3=343\)

Answer 10

so your last job is to compute
\[7+\frac{3}{4}\times (-2)\]

Answer 11

I got 5 1/2 (a)
thanks a lot :)
can you help me with just one more ?

Answer 12

square root of 32x^3y^5/-5 square root of 2xy

Answer 13

multiple choice:
1. 4xy^2/5
2. - 4xy^2/-5
3. 5xy^2/4
4. - 5xy^2/-4

Answer 14

let me try to write it
\[\frac{\sqrt{32x^3y^5}}{-5\sqrt{xy}}\] is that correct?

Answer 15

the first part is correct but you forgot to include a (2) before (xy)

Answer 16

\[\frac{\sqrt{32x^3y^5}}{-5\sqrt{2xy}}\]

Answer 17

perfect

Answer 18

ok then first step is to divide inside the radical and get
\[\frac{\sqrt{16x^2y^4}}{-5}\] then the take the square root in the numerator and get
\[\frac{4xy^2}{-5}\]

Answer 19

thank you so much for your help and time :)

Answer 20

i don't see the right answer though, are you sure you copied them correctly ?

Answer 21

yes, it's (b)

Answer 22

ok but there are two minus signs in b and there should only be one in the answer

Answer 23

oh that's right, I made a mistake but its b on my sheet :)