Question

An ordinary glass is filled to the brim with 322.6mL of water at 100.0 degrees C . If the temperature decreased to 20.0 C , how much water could be added to the glass? For the change in volume I multiplied coef. of volumetric thermal expansion (207*10^-6)(100-20 C)*(322.6mL). I got 5.34mL. I did convert celcius to Kelvin so the units cancel out. But either way you still get the same answer. The answer I got was wrong?? What do I need to do to fix this??

Answer 1

I get 5.52mL using 214*10-6 as you thermal expansion coefficient.

Answer 2

that is not the answer either :/

Answer 3

how about 18,23 ml?

Answer 4

and here is table, i think you need to use 100°C coefficient, if not try average between 20 and 100 or somethnig like that:
http://physchem.kfunigraz.ac.at/sm/Service/Water/H2Othermexp.htm

Answer 5

That is still is not the answer apparently I don't know what the right answer is supposed to be

Answer 6

Volume of the glass = 322.6mL
The Density variation with temperature is not leniar, so for large temperature differences it is better to refer to the density tables.
Mass remains constant, M=Density*Volume
D(20)*V(20)=D(100)*V(100)=Mass [V(20) == volume at 20deg celcius]
V(20)=D(100)*V(100)/D(20)
D(20)=998.2071 Kg/m3; D(100)=958.4 Kg/m3 (From Wikipedia)
V(20)=958.4*322.6/998.2071
=309.73mL
V extra = 322.6-309.73
=12.86mL

Answer 7

@MartialArtGirl647 are u there?