I REALLY need math homework help!! please respond! Please!!!
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Can you help me with this question? In a large population, very close to 25% of the observations will fall below the 25th percentile? (Q1), and close to 75% fall below the 75th percentile (Q3). The Web Site of the Educational Testing Service reports that on the SAT Verbal test, with a possible perfect score of 800, the 96th percentile of 1,475,623 scores nationwide is a score of 720 What is the best estimate of exactly how many scores were below 720
sorry been years since stats class. something to do with a z score:)
Thanks for responding, but I really need help with stats.
In a large population, very close to 25% of the observations will fall below the 25th percentile? (Q1), and close to 75% fall below the 75th percentile (Q3). The Web Site of the Educational Testing Service reports that on the SAT Verbal test, with a possible perfect score of 800, the 96th percentile of 1,475,623 scores nationwide is a score of 720 What is the best estimate of exactly how many scores were below 720
It states that "the 96th percentile ... is a score of 720", so this literally means that 96% of all the total scores were below 720 So just take 96% of the total (1,475,623) to get your estimate
Alright :) Thanks, do u have time to help with another question?
yw, sure go for it
Okay, just one sec....
ok
Make a modified boxplot for this distribution.. 25,34,46,37,33,42,40,37,34,49,73,46,45,45,5
Here's a good page that explains how to construct a modified box plot (and they provide examples as well) http://www2.selu.edu/Academics/Faculty/dgurney/Math241/StatTopics/BoxGen.htm Let me know if this helps or not
ok, thanks :)
you're welcome
shoot, I'm still having trouble.
which part are you stuck on
well, my math homework is multiple choice and the boxplots they have are really similar.
hmm can you show me?
Doesn't allow me to copy my homework ..
well maybe the scales are different even though the pics look the same?
it's hard to say without looking at the pic
That is true
does any of the pics have a star (or two) in them?
or a dot?
no
could it be that the last value in that list isn't a 5, but a 50 or something?
I answered it the best I could and it was correct and on the next question, its the same type of question though,
so basically another problem having you construct a modified box plot?
btw, I found this solver http://www.alcula.com/calculators/statistics/box-plot/ that will make box plots if you type in the data...I'm not sure if it does modified box plots though
Oh wait, never mind. sorry. They are asking me to find the first quartile
oh, find the median, then focus on the lower half and find the median to find the first quartile
in this distribution 24,26,26,27,28,31,33,35,37,38,40,42,43,46,48,55,56
I should state that you need to sort the data first and foremost.
so first step is to sort in ascending order (ie least to greatest)
it looks like that that is already done
now find the median
37
good
The median cuts the data set in half. So you have the lower half of 24,26,26,27,28,31,33,35 and the upper half of 38,40,42,43,46,48,55,56 ------------------------------------------------------- The first quartile Q1 is the median of the lower half
27?
not quite
27.5?
yes
ok :)...what is the interquartile range?
Interquartile range (IQR) is... IQR = Q3 - Q1 So you need the third quartile
So you do the same thing, but now to the upper half.
Side note: the IQR is basically the width of the box in the box and whisker plot
alright
They gave me a new distribution and are asking what that Q3 is
ok, do the same thing as you did before, but focus on the upper half this time Step 1) Find the median Step 2) Cut the data set into two halves **Different step** Step 3) Focus on the upper set and find the median to find Q3 **Different step**
okay so the numbers are 10,25,18,31,16,27,5,13,32,24,15,21,18,18,24,4,8,11,11,23
Oh I always forget, but remember to sort first
So start by sorting the data set 10,25,18,31,16,27,5,13,32,24,15,21,18,18,24,4,8,11,11,23
from least to greatest
4,5,8,10,11,13,15,16,18,23,25,31
one sec while I compare
ok
I see one copy of 11 in your list, but there are two "11" values
when I sorted, I got a much bigger list and I got 4,5,8,10,11,11,13,15,16,18,18,18,21,23,24,24,25,27,31,32
somehow, you got rid of the duplicate entries, but you actually want to keep them
Ohh, ok, soo the median is 18, right?
yes, the median is 18
and from 18 you cut it in half to get 18,21,23,24,24,25,27,31,32
that median is 24?
or is 24 the Q3 of the distribution?
you are correct
24 is the median of that upper half and it's the value of Q3
cool :)
Do you know anything about polynomials?
yes I do, what do you want to know about them?
well, how do I factor a number, variable or expression out the polynomial?
do you have a specific polynomial you want to work on?
5x(3x+1)+7(3x+1)
So what do you see in common here?
5x, 3x, 3x?
hmm let me restate it another way we have 5x(3x+1)+7(3x+1), which can be broken up into First term: 5x(3x+1) Second term: 7(3x+1) What is common among the two terms above?
(3x+1)
good, so you can factor it out of the entire expression
do you know how?
noo
Say we have 3x+5x, we can factor out the common term x to get x(3+5) So if we let z = 3x+1, we go from 5x(3x+1)+7(3x+1) to 5xz+7z Then we can factor out this common term z to get z(5x+7) Finally, we replace z with 3x+1 to get (3x+1)(5x+7)
okay, but it says to use ( 3x+1) and to factor out the number that each term as in common from the polynomial and multiply by the fully factored polynomial.
(3x+1) is that common factor and it's factored in the work shown above
why would it want to multiply by the fully factored polynomial?
hmm maybe they meant to multiply it out and check?
maybe...the next question seems more complicated. Its the same idea but with -3x^3 + 12x^2 + 36x
take it each term at a time First term: -3x^3 Second term: 12x^2 Third term: 36x What's the GCF here?
6
not quite
3?
getting better, but notice there are x terms in each term
so its 3x?
yes
what are the common terms?
3x is that common term, so factor it out and you can optionally factor out a negative to make that leading term positive to go from -3x^3 + 12x^2 + 36x to -3x(x^2 - 4x - 12)
Now can you factor x^2 - 4x - 12 at all?
I don't know how..
Find two numbers that multiply to -12 AND add to -4
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