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Mathematics 16 Online
OpenStudy (anonymous):

I REALLY need math homework help!! please respond! Please!!!

OpenStudy (zzr0ck3r):

?

OpenStudy (anonymous):

Can you help me with this question? In a large population, very close to 25% of the observations will fall below the 25th percentile? (Q1), and close to 75% fall below the 75th percentile (Q3). The Web Site of the Educational Testing Service reports that on the SAT Verbal test, with a possible perfect score of 800, the 96th percentile of 1,475,623 scores nationwide is a score of 720 What is the best estimate of exactly how many scores were below 720

OpenStudy (zzr0ck3r):

sorry been years since stats class. something to do with a z score:)

OpenStudy (anonymous):

Thanks for responding, but I really need help with stats.

OpenStudy (anonymous):

In a large population, very close to 25% of the observations will fall below the 25th percentile? (Q1), and close to 75% fall below the 75th percentile (Q3). The Web Site of the Educational Testing Service reports that on the SAT Verbal test, with a possible perfect score of 800, the 96th percentile of 1,475,623 scores nationwide is a score of 720 What is the best estimate of exactly how many scores were below 720

jimthompson5910 (jim_thompson5910):

It states that "the 96th percentile ... is a score of 720", so this literally means that 96% of all the total scores were below 720 So just take 96% of the total (1,475,623) to get your estimate

OpenStudy (anonymous):

Alright :) Thanks, do u have time to help with another question?

jimthompson5910 (jim_thompson5910):

yw, sure go for it

OpenStudy (anonymous):

Okay, just one sec....

jimthompson5910 (jim_thompson5910):

ok

OpenStudy (anonymous):

Make a modified boxplot for this distribution.. 25,34,46,37,33,42,40,37,34,49,73,46,45,45,5

jimthompson5910 (jim_thompson5910):

Here's a good page that explains how to construct a modified box plot (and they provide examples as well) http://www2.selu.edu/Academics/Faculty/dgurney/Math241/StatTopics/BoxGen.htm Let me know if this helps or not

OpenStudy (anonymous):

ok, thanks :)

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (anonymous):

shoot, I'm still having trouble.

jimthompson5910 (jim_thompson5910):

which part are you stuck on

OpenStudy (anonymous):

well, my math homework is multiple choice and the boxplots they have are really similar.

jimthompson5910 (jim_thompson5910):

hmm can you show me?

OpenStudy (anonymous):

Doesn't allow me to copy my homework ..

jimthompson5910 (jim_thompson5910):

well maybe the scales are different even though the pics look the same?

jimthompson5910 (jim_thompson5910):

it's hard to say without looking at the pic

OpenStudy (anonymous):

That is true

jimthompson5910 (jim_thompson5910):

does any of the pics have a star (or two) in them?

jimthompson5910 (jim_thompson5910):

or a dot?

OpenStudy (anonymous):

no

jimthompson5910 (jim_thompson5910):

could it be that the last value in that list isn't a 5, but a 50 or something?

OpenStudy (anonymous):

I answered it the best I could and it was correct and on the next question, its the same type of question though,

jimthompson5910 (jim_thompson5910):

so basically another problem having you construct a modified box plot?

jimthompson5910 (jim_thompson5910):

btw, I found this solver http://www.alcula.com/calculators/statistics/box-plot/ that will make box plots if you type in the data...I'm not sure if it does modified box plots though

OpenStudy (anonymous):

Oh wait, never mind. sorry. They are asking me to find the first quartile

jimthompson5910 (jim_thompson5910):

oh, find the median, then focus on the lower half and find the median to find the first quartile

OpenStudy (anonymous):

in this distribution 24,26,26,27,28,31,33,35,37,38,40,42,43,46,48,55,56

jimthompson5910 (jim_thompson5910):

I should state that you need to sort the data first and foremost.

jimthompson5910 (jim_thompson5910):

so first step is to sort in ascending order (ie least to greatest)

jimthompson5910 (jim_thompson5910):

it looks like that that is already done

jimthompson5910 (jim_thompson5910):

now find the median

OpenStudy (anonymous):

37

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

The median cuts the data set in half. So you have the lower half of 24,26,26,27,28,31,33,35 and the upper half of 38,40,42,43,46,48,55,56 ------------------------------------------------------- The first quartile Q1 is the median of the lower half

OpenStudy (anonymous):

27?

jimthompson5910 (jim_thompson5910):

not quite

OpenStudy (anonymous):

27.5?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

ok :)...what is the interquartile range?

jimthompson5910 (jim_thompson5910):

Interquartile range (IQR) is... IQR = Q3 - Q1 So you need the third quartile

jimthompson5910 (jim_thompson5910):

So you do the same thing, but now to the upper half.

jimthompson5910 (jim_thompson5910):

Side note: the IQR is basically the width of the box in the box and whisker plot

OpenStudy (anonymous):

alright

OpenStudy (anonymous):

They gave me a new distribution and are asking what that Q3 is

jimthompson5910 (jim_thompson5910):

ok, do the same thing as you did before, but focus on the upper half this time Step 1) Find the median Step 2) Cut the data set into two halves **Different step** Step 3) Focus on the upper set and find the median to find Q3 **Different step**

OpenStudy (anonymous):

okay so the numbers are 10,25,18,31,16,27,5,13,32,24,15,21,18,18,24,4,8,11,11,23

jimthompson5910 (jim_thompson5910):

Oh I always forget, but remember to sort first

jimthompson5910 (jim_thompson5910):

So start by sorting the data set 10,25,18,31,16,27,5,13,32,24,15,21,18,18,24,4,8,11,11,23

jimthompson5910 (jim_thompson5910):

from least to greatest

OpenStudy (anonymous):

4,5,8,10,11,13,15,16,18,23,25,31

jimthompson5910 (jim_thompson5910):

one sec while I compare

OpenStudy (anonymous):

ok

jimthompson5910 (jim_thompson5910):

I see one copy of 11 in your list, but there are two "11" values

jimthompson5910 (jim_thompson5910):

when I sorted, I got a much bigger list and I got 4,5,8,10,11,11,13,15,16,18,18,18,21,23,24,24,25,27,31,32

jimthompson5910 (jim_thompson5910):

somehow, you got rid of the duplicate entries, but you actually want to keep them

OpenStudy (anonymous):

Ohh, ok, soo the median is 18, right?

jimthompson5910 (jim_thompson5910):

yes, the median is 18

OpenStudy (anonymous):

and from 18 you cut it in half to get 18,21,23,24,24,25,27,31,32

OpenStudy (anonymous):

that median is 24?

OpenStudy (anonymous):

or is 24 the Q3 of the distribution?

jimthompson5910 (jim_thompson5910):

you are correct

jimthompson5910 (jim_thompson5910):

24 is the median of that upper half and it's the value of Q3

OpenStudy (anonymous):

cool :)

OpenStudy (anonymous):

Do you know anything about polynomials?

jimthompson5910 (jim_thompson5910):

yes I do, what do you want to know about them?

OpenStudy (anonymous):

well, how do I factor a number, variable or expression out the polynomial?

jimthompson5910 (jim_thompson5910):

do you have a specific polynomial you want to work on?

OpenStudy (anonymous):

5x(3x+1)+7(3x+1)

jimthompson5910 (jim_thompson5910):

So what do you see in common here?

OpenStudy (anonymous):

5x, 3x, 3x?

jimthompson5910 (jim_thompson5910):

hmm let me restate it another way we have 5x(3x+1)+7(3x+1), which can be broken up into First term: 5x(3x+1) Second term: 7(3x+1) What is common among the two terms above?

OpenStudy (anonymous):

(3x+1)

jimthompson5910 (jim_thompson5910):

good, so you can factor it out of the entire expression

jimthompson5910 (jim_thompson5910):

do you know how?

OpenStudy (anonymous):

noo

jimthompson5910 (jim_thompson5910):

Say we have 3x+5x, we can factor out the common term x to get x(3+5) So if we let z = 3x+1, we go from 5x(3x+1)+7(3x+1) to 5xz+7z Then we can factor out this common term z to get z(5x+7) Finally, we replace z with 3x+1 to get (3x+1)(5x+7)

OpenStudy (anonymous):

okay, but it says to use ( 3x+1) and to factor out the number that each term as in common from the polynomial and multiply by the fully factored polynomial.

jimthompson5910 (jim_thompson5910):

(3x+1) is that common factor and it's factored in the work shown above

OpenStudy (anonymous):

why would it want to multiply by the fully factored polynomial?

jimthompson5910 (jim_thompson5910):

hmm maybe they meant to multiply it out and check?

OpenStudy (anonymous):

maybe...the next question seems more complicated. Its the same idea but with -3x^3 + 12x^2 + 36x

jimthompson5910 (jim_thompson5910):

take it each term at a time First term: -3x^3 Second term: 12x^2 Third term: 36x What's the GCF here?

OpenStudy (anonymous):

6

jimthompson5910 (jim_thompson5910):

not quite

OpenStudy (anonymous):

3?

jimthompson5910 (jim_thompson5910):

getting better, but notice there are x terms in each term

OpenStudy (anonymous):

so its 3x?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

what are the common terms?

jimthompson5910 (jim_thompson5910):

3x is that common term, so factor it out and you can optionally factor out a negative to make that leading term positive to go from -3x^3 + 12x^2 + 36x to -3x(x^2 - 4x - 12)

jimthompson5910 (jim_thompson5910):

Now can you factor x^2 - 4x - 12 at all?

OpenStudy (anonymous):

I don't know how..

jimthompson5910 (jim_thompson5910):

Find two numbers that multiply to -12 AND add to -4

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