Question

Find the exact value of the radical expression in simplest form.
2 the square root of 7 times x + the square root of 7 times x - 3 the square root of 7 times x - 7

Answer 1

Answer choices
-7

4 the square root of 7 times x - 7

the square root of 7 times x

3 the square root of 7 times x - 7

Answer 2

\[2\sqrt{7x}+\sqrt{7x}-3\sqrt{7x}-7\]

Answer 3

@ash2326

Answer 4

I dont understand this

Answer 5

@Tennistar it's quiet easy if you have
\[2x+x-3x\]
How would you simplify this?

Answer 6

* quite
sorry

Answer 7

ummm I dont know

Answer 8

ok, what's
\[2+1-3\]
???

Answer 9

0

Answer 10

Good, so if we have
\[2x+x-3x\]
We can notice all the terms have x here, so we'll simplify it using normal arithmetic just like you did for (2+1-3)
So what would get here?
@Tennistar

Answer 11

0 right

Answer 12

Yeah , if we have
\[2x+x-x\]
What would you get?

Answer 13

because you remove the x from all parts by dividing

Answer 14

can you help me solve it step by step

Answer 15

Yeah we divide all the terms by x and place it outside the bracket
When you solved
\[2x+x-3x\]
You actually did
\[x(2+1-3)\]
\[x\times 0=>0\]

Answer 16

Yeah, I'll help you
Did you understand this?

Answer 17

I really need to know and yes

Answer 18

okay here we have
\[2\sqrt{7x}+\sqrt{7x}-3\sqrt{7x}-7\]
Notice the first three terms
\[\underline{2\sqrt{7x}+\sqrt{7x}-3\sqrt{7x}}-7\]
First simplify them, just like you did for \((2x+x-3x\))
try this

Answer 19

so divide by 7x*sqrt all parts?

Answer 20

Yeah, divide and take it outside and then simplify the numbers

Answer 21

adn have 2 + 1-3-7

Answer 22

-7

Answer 23

where?

Answer 24

Sorry, yeah, you're right. I'll show you the step wise approach

Answer 25

\[2\sqrt{7x}+\sqrt{7x}-3\sqrt{7x}+7\]
Take \(\sqrt{7x}\) common from the first three terms
\[\sqrt{7x}(2+1-3)-7\]
\[\sqrt{7x}\times 0-7=>-7\]
voila

Answer 26

Do you get this?

Answer 27

yes

Answer 28

@Tennistar I really liked that you are so eager to learn. good work and way to go :)