graph (x^2+2x+5)/(x+3)

Question

hy123 · Answer

Anybody?

anonymous · Answer

without a graphing calculator?

hy123 · Answer

Well i just need points to plot and the asymptotes

anonymous · Answer

ok... so first determine the domain of this expression.... what is it?

hy123 · Answer

It is x cannot be -3

anonymous · Answer

good... so we have a vertical asymptote at x=-3..

anonymous · Answer

now do you know how to find the other asymptotes (horizontal, slant)?

hy123 · Answer

Wait typo in the equation
Suppose to be
(x^2+2x-5)/(x+3)

anonymous · Answer

doesn't matter, do you know how to locate horizontal or slant asmymptotes?

hy123 · Answer

Nope.

campbell_st · Answer

well the vertical asymptote is x = -3
 
the oblique asymptote is found by polynomial division or synthetic division


the line y = x - 1

then the curve is a squashed hyperbola between the asymptotes

anonymous · Answer

here is the procedure for rational functions...
if $\lage f(x)=\frac{N(x)}{D(x)} $, and N(x) and D(x) are polynomials then you will have a slant asymptote if the degree of the numerator is 1 more than the degree of the donominator..

hy123 · Answer

Yeah something to do with the degrees. So there is a slant?

anonymous · Answer

this is just for the slant asymptote.. we don't need to find horizontal because if you have a slant asymptote, you do not have a horizontal asymptote..

anonymous · Answer

do you want me to put in the requirements for horizontal also?

campbell_st · Answer

|dw:1341090117677:dw|