Question

The equation of circle having a diameter with endpoints (-3, 1) and (5, 7) is

Answer 1

midpoint of line joining these points is center of circle
half length is radius

then substitute in the general form
(x-a)^2 + (y-b)^2 = r^2

Answer 2

A.(x - 4)² + (y - 3)² = 25
B.(x - 1)² + (y - 4)² = 25
C.(x - 1)² + (y - 4)² = 100

Answer 3

sqrt( (7-1)^2 + (5- (-3))^2 ) is the radius
so (x+3)^2 + (y-1)^2 = 100

Answer 4

c?

Answer 5

hmm did i do something wrong? or is the answer not listed?

Answer 6

the centre is the mid point of the interval

the radius is the distance from the centre to an endpoint

centre: x = (5 -3)/2 y = (7 + 1)/2

centre is (1, 4)

Radius:
\[r = \sqrt{(5 - 1)^2 +(7 - 4)^2}\]

\[r = \sqrt{18}\]

then the equation is

\[(x - 1)^2 + (y - 4)^2 = 18\]

you can expand and simplify the equation

Answer 7

oops radius = 5 so r^2 = 25

Answer 8

ahh yes "the diameter has endpoint" sorry

Answer 9

yes ... diameter is 10 ... so radius is 5

Answer 10

whats the answer then