Question

What are the foci of the following graph?

Answer 1

the foci is obtained by adding "c" above and below the center of your hyperbola where
\(\c^2=a^2+b^2 \), where 2a, 2b are the lengths of your conjugate and transversal axis, repectively.

Answer 2

:) did that make any sense at all?

Answer 3

ok look girl, dont panic, everythings okay

Answer 4

first, for all graph SQUEEZED in the center, has foci on the vertical axe

Answer 5

now listen girl, no matter how squeezed it is (vertically in case of this graph) or horizontally, the magic formula to find out the distance between FOCI AND CENTER is always:
\[c^2 = a^2 + b^2\]

Answer 6

C is the distance between FOCI AND CENTER

Answer 7

(-3, 0) and (3, 0)

(0, -3) and (0, 3)

(- square root 34,0) and (square root 34, 0)

(0, - square root 34) and (0, square root 34 )

Answer 8

... you're gonna have to do what the helpers are asking you to do...

Answer 9

look, remember this, if the graph is squeezed vertically, than the focis are on the vertical axe, THUS either

(0, - square root 34) and (0, square root 34 )
or
(0, -3) and (0, 3)

Answer 10

a is always half of the rectangle's width
b is always half of the rectangle's length
c is always the distance between the center of the rectangle, to one of the foci

Answer 11

so its between b or c

Answer 12

ye..

Answer 13

Yao Ming is laughing and crying at the same time