Stable High School has a total of 112 boys and girls who play sports. If the number of boys, b is 16 more than twice the number of girls, g, how many boys play sports at this high school? Which system of equations would help you solve this problem?
here are the choices A- b + g = 112 b = 2g + 16 B- b + g = 112 g = 2b + 16 C- b − g = 112 b = 2g − 16 D- None of the systems above would solve this problem.
B + 16 = 2G B + G = 112 Ans. is C
It can't be C I think, because it says -16, when in the problem it says 16 more than
So it would be A or D
@mrtdmr26
Really I think the answer is D. The equations are: b+16=2g and b+g=112. The system has not integer answer
Yea that's what I think too
B + 16 = 2G B = 2G - 16 Clear or not :)
I think the answer is A personally, but I do see where you are coming from.
If i were you i chose C Because that is an equation... :) You can move elements in it...
But b - g = 112 is subtracting the boys from the girls. The problem states that the boys AND girls combined equals 112. And the 2nd part of the equation says b = g2 - 16, but it says 16 MORE than twice as much than the girls. So that is my thinking.
I say A.
My english is not too good but I´ll try to explain. Answer A: the 2nd eq is wrong. the problem says 16 + (more) than 2g and not 16+(plus) 2g. Ans B: Is a similar error. Ans C:All boys and girls are 112. Hope it helps
Ohh, sorry, i cant seen minus between B and G :(
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