Question

(sin 60 degree)^2(sec 240 degree)+(tan 45 degree)(cos 225 degree)^2 = ?

Answer 1

\[\sin60 = \frac{\sqrt{3}}{2}\]

\[\sec(240) = \sec(180 + 60) = -\sec60 = -2\]

\[\tan45 = 1\]

\[\cos(225) = \cos(180 + 45) = -\cos45 = \frac{-1}{\sqrt{2}}\]

Put these values in the above expression and solve to get your answer..

Answer 2

Huh?

Answer 3

\[(\sin60)^2.(\sec240) + (\tan45).(\cos225)^2\]

I have provided you the values just plug in and try to solve further..

Answer 4

you basically just wrote it again. i dont know how to solve it, so i need help solving it.

Answer 5

What is the values of sin60??
Just reply..

Answer 6

square root 3/2

Answer 7

Yes..
Plug in the question this value..

Now tell me what is value of sec240??

Answer 8

-2

Answer 9

Like wise I have given all the values..
So, what you have to do is to plug in these values in the question..
What is problem in that?

Answer 10

i dont know how to add fractions.

Answer 11

Just plug in the values and then show me..
I will help in solving further..

Answer 12

especially when there is square root

Answer 13

I will tell you the whole thing but show me your work after plugging in the values..

Answer 14

square root 3/2 * -2

Answer 15

Further??

Answer 16

See there is square of sin60 term..
so what will be the square of root(3)/2??

Answer 17

square root 6/4 ?

Answer 18

Do you know how to square??

Answer 19

plain numbers yes, square roots, no!

Answer 20

Use the following formula and tell me then the square of root(3):

\[\sqrt{a} \times \sqrt{a} = (\sqrt{a})^2 = a\]

Tell me now the square of root(3)??

Answer 21

SR3*SR3=(SR3)^2=9?

Answer 22

Great..!

What is the value of a??
See,

Compare \[\sqrt{a}\] with the \[\sqrt{3}\]

and tell me what is a here??

Answer 23

SR3a?