Solve x2 + 9x + 9 = 0. using quadratic formula
So here is a hint : \[\huge{x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}}\]
where a,b,c are coeffiecients of a quadratic eqn. ax^2+bx+c
x is root of the quadratic equation : \(\huge{ax^2+bx+c=0}\)
substitute a,b,c in the formula to get x u will get 2 values as there are 2 roots of a quad. eqn.
is it -9root117 all over 2?
guys i dont get this man..all of my answer choices have a 10 at the end
oops sorry wrong question.
@rayford you got it?
is it -9 + or minus root 117 all over 2?
check again, there is a small mistake Check the term in square root
3root5?
Correct, it'd be \[\frac{-9\pm 3\sqrt 5}{2}\]
YES!!!!!! 100 ON MY EXAM YEAS!! ty i understand now :[)
@rayford were you giving a test?
oh no! i was stating that 100 on my exam here i come. cause now that i understand i will do good on my exam :]
Great:D wish you great luck with that. Let me know whenever you need help here. :D
thank you very much. lol champion
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