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Mathematics 11 Online
OpenStudy (anonymous):

Can anyone help me with proofs.?

OpenStudy (king):

yeah sure why not....

OpenStudy (anonymous):

OpenStudy (anonymous):

Statements Justifications In triangles APD and BPC; DP = PC Sides of equilateral triangle DPC are equal In triangles APD and BPC; AD = BC Sides of square ABCD are equal In triangles APD and BPC; angle ADP = angle BCP Angle ADC = angle BCD = 90° so angle ADP = angle BCP = 60° Triangles APD and BPC are congruent SAS postulate

OpenStudy (anonymous):

whats the error

OpenStudy (king):

i dont get it what do u want me to prove and what is given?

OpenStudy (king):

oh ok...wait...

OpenStudy (king):

first justification,is it already given that DPC is an equilateral triangle?

OpenStudy (anonymous):

no

OpenStudy (king):

2nd justification is it already given that ABCD is a square?

OpenStudy (anonymous):

You know, i don't really find anything wrong with your justification!

OpenStudy (king):

3rd justification,is it already given that Angle ADP and Angle BCP are of measure 90 degrees?

OpenStudy (anonymous):

He writes the measure of angles ADP and BCP as 60° instead of 45°. He uses the SAS postulate instead of AAS postulate to prove the triangles congruent. He writes the measure of angles ADP and BCP as 60° instead of 30°. He uses the SAS postulate instead of SSS postulate to prove the triangles congruent.

OpenStudy (king):

what/who is 'he'?

OpenStudy (king):

are these options?

OpenStudy (anonymous):

yes

OpenStudy (king):

is it given that ABCD is a square?

OpenStudy (anonymous):

im pretty sure thats known

OpenStudy (king):

ok then the justification 3 is wrong as angle ADP,angle BCP cant be 90 as ADC is 90 and angle PDC is 60 so angle ADP is 30 similarly BCP is also 30

OpenStudy (king):

He writes the measure of angles ADP and BCP as 60° instead of 30°.but u used 90 so idk

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