Need help understanding integrals. I'm not sure if I'm typing it correctly, but here's the question: Find the definite integral 4 to 1 (x^2-4sqrtx)/x Wolfram alpha keeps saying the answer is 1/2, but I keep getting -7.5. I'm pretty sure my answer is correct, but I'm never confident with my answers... is there some kind of rule when doing subtraction?
When you say integral 4 to 1 do you mean \[\int\limits_{4}^{1} or \int\limits_{1}^{4}\] ?
the second one
squiggly s with 4 on top :p
Oh ok then for future reference you should make sure you say "1 to 4," always say the bottom number to the top number.
Bad Religion, regurgitate. Indecision, it's not too late.
I'm sorry if a lot of my questions are a bit remedial, but the only way I can learn this stuff for sure is to have someone validate my thinking :p. haha. but I mean, I understand the concept that the integral is basically just the area under the curve.
All questions are good questions because it means you're learning something from them so never worry about sounding 'remedial.' I just wanted to be sure your question was interpreted correctly. So you can split up your integral into two integrals:\[\int\limits_{1}^{4} x ^{2}/x - \int\limits_{1}^{4} 4\sqrt{x}/x\] The first integral reduces down to just x, and the integral of x is 1/2x^2. Evaluated from 1 to 4,\[1/2(4)^{2} - 1/2(1)^{2} = 1/2(16)-1/2(1)=8-1/2=7.5\] Then the second integral reduces down to just 4/sqrt(x) (do you know how?) or written as \\[\int\limits\limits_{1}^{4} 4x ^{-1/2} = 4*(2x ^{1/2})=8x ^{1/2}\] Evaluated from 1 to 4, that is: \[8(4)^{1/2} - 8(1)^{1/2} = 8(2)-8(1)=16-8=8\] So the result from your first integral was 7.5 and the result from your second integral was 8. Your first integral minus your second integral = 7.5-8 = -1/2
ahh ok i see. So If I have substraction or addition, I split the equation into parts and take the definite integral of each part separately, right?
Correct :)
sweet :) Thank you so much for the help :D. I think math is one of the few subjects where you can actually get a definite answer to almost anything ;p
and it's not ridiculously subjective and biased...xD
No problem. Haha yes it can be satisfying to get a straight answer from math when so much of the rest of academia and the world itself is questionable :) Let me know if you need any more help with integrals!
thank you :). I will probably have a few more questions as soon as this stuff gets harder haha.
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