Question

(4x)^-2
positive exponent
I came up with 1/62x^2

Answer 1

\[(4x)^{-2}\] is the same as

\[\frac{1}{(4x)^2}\]

Answer 2

using this when you have
\[(4x)^2=4^2x^2\]

Answer 3

does this make sense

Answer 4

\[a^{-n}=\frac{1}{a^n}\]

Answer 5

so the answer would be 1/a^n?

Answer 6

outkast's very first post gives you the answer.

you could also write it as
\[\frac{1}{16x^2} \]

Answer 7

1/16x^2 can be wrote as a positive exponent?

Answer 8

I guess your question is:
Can (4x)^-2 be writen as a positive exponent?
And the answer is: yes 1/(4x)^2 or 1/16x^2

Answer 9

Not sure I understand your question: 1/16x^2 can be wrote as a positive exponent?

It is a positive exponent. That is the answer to your original question.

Answer 10

oh okay thanks.
so I had the wrong answer 1/62x^2?

Answer 11

the 62 or is that 6^2? is wrong. the 1/x^2 part is correct.
you change \( (4x)^{-2} \) to \( \frac{1}{(4x)^{2}} \)

the idea is not too complicated: flip the fraction and negate the exponent.

Answer 12

so you can do
\[ \frac{1}{(4x)^{-2} }= \frac{(4x)^2}{1} = (4x)^2 \]
flip the fraction and negate the exponent. negate means change - to + or + to -