How do I solve this Matrix equation requiring inverses?
My guess is that I find the inverse of -1 -9 0 -1 then multiply it by 11 2?
Please note I haven't learned this before and this is the way i'm going to learn it, but I have a strong grasp on matrix inverses and multiplication, etc
That's correct.
Nonhomogeneous matrix equations of the form AX=B can be solved by taking the matrix inverse to obtain X=A^(-1) B so u r right
Alright, sweet. However, I don't understand what AX=B means... or what nonhomogenous means?
ok
A is the matrix. X is the vector you're trying to solve for (C in your example) and B is the right hand side. In this case the column vector (11, 2) . A homogeneous equation is one that looks like AX=0. Non-homogeneous is when the RHS is non-zero.
Thank you so much again :D. But what does the right hand side being zero have to do with anything? Why is it important?
When the right hand side is 0 you are guaranteed to have a solution (the 0 vector). Sometimes you have an infinite number of solutions even for Ax=b. The way to find all of them is to find all the solutions for Ax*=0 and ONE particular solution for Ax=b. By adding that one x to each of the x* that solved the homogeneous equation you get all the solutions of the non-homogeneous equation.
One small note, you can't always solve these equations using inverses. A might not have an inverse even when the equation has a solution. Actually, when there are infinitely many solutions the matrix A won't have an inverse.
I don't understand "The way to find all of them is to find all the solutions for Ax*=0 and ONE particular solution for Ax=b. " Does that mean that the matrix I solved for, which is 7 -2 isn't a solution?? What do you mean by having an infinite number of solutions? And how would I solve it when A doesn't have an inverse?
Join our real-time social learning platform and learn together with your friends!