Which polynomial is written in descending order?
\[9-3x+4x ^{2}\] \[-3x+9+4x ^{2}\] \[4x ^{2}+9-3x\] \[4x ^{2}-3x+9\]
you want the biggest powers (the little number on the upper right of the x) first, left to right.
What? I don't get it..
you want the x^2 term first, the x term second and the constant last. Which of the 4 answers is in that order?
big to small
\[\Large x^9 + 2x^8 + 15x^7 -2x^6 +x^4 -30x^3 -10x^2\] There's an example of a polynomial in descending order.
\[\Large x +30x^2\] There's an example of a polynomial that's NOT in descending order.
notice that you use the exponent to decide who goes first. the other numbers (coefficients) don't matter.
So, the answer is \[9-3x+4x ^{2}\]
the other way round.
Oh.. \[4x ^{2}-3x+9\] ?
Yes. That is standard form. Did you know that \( x^0 =1 \)? so we could write this as \[ 4x^2-3x^1+9x^0 \] do you see the pattern 2 1 0 (the exponents go down)
I'm lost..
what is your question?
when you have a problem like this |dw:1341185099195:dw|
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