how do you solve this differential equation? (y+1)dx+(4x-y)dy=0 ??
I was going to say split it up (y+1)dx+(4x-y)dy=0 dx/(4x-y)=-dy/(y+1)
But you are still left with a y in the left side.
yeah xD
Sorry just throwing out ideas hoping you might catch something.
@shinigami1m you can use exact differential equation...do you know how to use that?
wait i mean integrating factor for exact differential equation
like partial M and partial N?
you can also use the bloody and morbid homogeneous
Oh is this when you take a derivative of each one plug it in to each other integrate and so on?
@shinigami1m this is what im talking about...it's not discussed in most schools so i dont know if you know it... http://openstudy.com/updates/4fd16ab5e4b057e7d220ae39
Gj on the tutorial @lgbasallote
i know that method :D
i got (y+1)^3 for integrating factor
wait..why? \[\frac{\partial M}{\partial y} - \frac{\partial N}{\partial x} = 4 - 1 = 3\] right?
yes
wait i mean -3
umm its 1-4
it's 1- 4
then you divide it by M so you have \[-\frac{3}{y+1}\] right? btw thanks @Romero
yep
then you use \[e^{-\int g(y)dy}\] right?
yeeeee
so you have \[\huge e^{\int \frac{3}{y+1}dy}\] agree?
agree
lol yeah it's (y+1)^3 sorry :p haha
HAHA the hard part is the next part... :| distributing I.F.!!
so i guess using homogeneous is easier in this one :/
its not homogenous i think
hmm yeah...darn y+1 -_-
how about linear DE?
it's linear in y
\[\frac{dx}{dy} + (\frac{4}{y+1})x = \frac{y}{y+1}\]
i'm at the final part... i just need to integrate -y(y+1)^3dy~~~~
lol this is nice...there are a lot of ways to solve this... which method did you use?
exactness i just continued it haha... i think linearity is easier
yeah it is lol
IF = (y+1)^4 i think
that is if we use linearity haha y(y+1)^3 on the other side still XD but i got the answer hhehe
I always like youtubing these to see how other people do it. I like this one http://www.youtube.com/watch?v=bwASJWS8ltM You know I hear that you are able to retain information better if you do more study more than one way. Like reading and hearing other people then you doing it by yourself.
So I hope that helps.
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