Question

Dividing Radical Expressions
Find the value of the square root of 6 over 5 times the square root of 3. in simplest form.

2 over 5.

3 over 4.

the square root of 15 over 5.

the square root of 2 over 5.

Answer 1

how did you get that?

Answer 2

ok... what about

\[\frac{\sqrt{6}}{5\sqrt{3}}\]

Answer 3

yes that. how do i simplify that

Answer 4

rationalise the denominator by multiplying by
\[\frac{\sqrt{3}}{\sqrt{3}}\]

\[\frac{\sqrt{6}}{5\sqrt{3}}\times \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{6 \times3}}{5\times \sqrt{3\times3}}\]

just simplify and eliminate common factors

Answer 5

ok so would the final answer be 2 over 3 then?

Answer 6

i mean 2 over 5

Answer 7

no its \[\frac{ 3\sqrt{2}}{ 3 \times5} = \frac {\sqrt{2}}{5}\].

Answer 8

ok. why does the squared stay there ?

Answer 9

i dont understand that part

Answer 10

find the factors of 18... looking for one that is a square number...

\[\sqrt{18} = \sqrt{9\times2} = \sqrt{9} \times \sqrt{2} = 3\sqrt{2}\]

2 is not a square number so needs to remain as a radical

Answer 11

oooh ok i get it now. thank you.

Answer 12

hope it helps