Question

2x^2+2x=20 use thee discriminant to find the number of unique real solutions

Answer 1

so 2x^2 + 2x -20=0
x^2 + 2 -10 = 0
-2 +- sqrt(2^2-4(1)(-10)))/(2a)
make sence so far?

Answer 2

yeah

Answer 3

so the disceiminant is 2^2 - 4(1)(-10)

Answer 4

discriminant > 0 2 real solutions
discriminant = 0 1 real solution
discriminant < 0 0 real soutions

Answer 5

got it?

Answer 6

yeah. Thank you

Answer 7

By comparing the given equation with the standard:

\[ax^2 + bx + c= 0\]

You have a = 2, b =2 and c = -20

So formula for D is:

\[D = b^2 = 4ac\]

Plug in the values and find D..