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Physics 7 Online
OpenStudy (anonymous):

1. Two objects are thrown from the same point into the opposite directions (both directed horizontally) as shown on the picture with initial velocities V1=3 m/s and V2=4 m/s. Find distance l between the objects at the moment when they have mutually perpendicular velocities.

OpenStudy (anonymous):

attached is the pic of the system

OpenStudy (anonymous):

please help me someone!!!!

OpenStudy (queelius):

vector v1 = <9.8t, -3> vector v2 = <9.8t, 4> v1 is orthogonal to v2 when dotproduct(v1, v2) = 0. So,9.8^2t^2-12=0; 9.8^2t^2 = 12; t^2 = 12/9.8^2; t = sqrt(12/9.8^2) That gives you time t for when their vectors are orthogonal. Now, how do you solve the next part to determine distance at time t?

OpenStudy (anonymous):

@queelius: so the answer is \[10\sqrt{3} / 7\] ? am I right?

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