Question

How do you find the minimum of the graph y=x^2-3x+1?

(the points of the minimum)

Answer 1

use the magic formula \(-\frac{b}{2a}\) to get the first coordinate of the vertex
second coordinate is the minimum

Answer 2

in your case \(-\frac{b}{2a}=-\frac{-3}{2\times 1}=\frac{3}{2}\) replace \(x\) by \(\frac{3}{2}\) and see what you get

Answer 3

great explanation satallite :D

Answer 4

i like the magic formula,
it is easy to prove
real easy to use
and only contains five symbols: minus sign, fraction bar, the number 2 and the variables \(a\) and \(b\)

Answer 5

differentiate the equation and equate to zero

Answer 6

what means "differentiation"?

Answer 7

I think that is out of scope for the OP @DHASHNI

Answer 8

\(y=ax^2+bx+c=a(x+\frac{b}{2a})^2+k\) vertex is clearly at \((-\frac{b}{2a},k)\) since the first term is a perfect square and is therefore either at most zero or at least zero, depending on the sign of \(a\)

Answer 9

OP?

Answer 10

Oringal Poster

Answer 11

you down with OP P?

Answer 12

y'=2x-3
equating it to zero
2x-3=0
2x=3
x=3/2

Answer 13

http://www.youtube.com/watch?v=mJgFU3U4X_Y

Answer 14

so the points are (1.5, -1.25)? (:

Answer 15

I like OPP

Answer 16

LOL!!!

Answer 17

Other peoples property?

Answer 18

"propery" maybe ...

Answer 19

@Genuine yes you are right

Answer 20

YAY! Thank you so much for helping me today @satellite73

Answer 21

yw