Choose the value of the coefficient determinant (D) in the following system. 2x – 5y = –2 x – 3y = 0
The coefficient matrix is made up of the coefficients of x and y: \[\left[\begin{matrix}a & b \\ c & d\end{matrix}\right] = \left[\begin{matrix}2 & -5 \\ 1 & -3\end{matrix}\right]\] The determinant of that is found by multiplying the diagonal terms and subtracting them in the form of ad-bc: \[\left| \left[\begin{matrix}2 & -5 \\ 1 & -3\end{matrix}\right] \right| = 2(-3)-(-5)(1)=-6+5=-1\]
Choose the value of the x determinant (Dx) in the following system. 3x – 4y = –7 x + y = 7
their is an x?? instead of just an an x
d i mean
Hmm I am not sure what is meant by "x determinant." I don't believe I've heard that term before. However here is a link to a question similar to yours, perhaps the answer there can help you: http://answers.yahoo.com/question/index?qid=20101219091339AAmbZLk
What are the choices of values you are supposed to choose from?
21 28 -14 -35
Ok if you use the method the person used in that link I posted, you will get a number that is included in those choices you listed.
its 35! :[)?
Well that is not what I got. Show me what you did.
[3.4] [1.1] 4-3=1 -7.4 7.1 28+7=35??
Your answer is a little confusing. Why are you doing 4-3=1? Note: your "D" coefficient matrix needs to have a -4, not 4.
so the answer is -35?
No, how would you get -35? Plug in the -4 in and see what you get when you do the math. \[\left[\begin{matrix}-7 & -4 \\ 7 & 1\end{matrix}\right] = ?\]
(-7)(1)-(-4)(7)=-7+28 = ...?
ohhhhhh....thats how i got 35..i got the negatives mixed up..
its 21 ok..
Yep, just had to have a -4 instead of a 4. If the method that person in the link posted is correct, then your answer should be correct.
may you do one more?
Choose the value of the y determinant (Dy) in the following system. 2x – 4y = 24 2x – 3y = 15 –132 –12 –18 78
Well now that you have done one, you should be able to do another one, using that same method. I assume now that it's y instead of x though, you use the x column (2,2) instead of the y column like in the previous problem.
well can you atleast check my answer :3?
Sure.
-12?
Well, you get -12 if you use the y coefficients (-4,-3) like in the previous problem, which asked you for the x determinant, so I assume that -12 is your x determinant. If you want the y determinant, I assume you have to use the x coefficients then (2,2)... but that gives me an answer of 18, not -18 like in your choices. So I am uncertain here -- hopefully someone else can pick it up.
it was 18..... thank you and goodnight
Oh okay. You are welcome. Good night :)
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