A 50-N ⋅ m torque acts on a wheel with a moment of inertia 150 kg ⋅ m2. If the wheel starts from rest, how long will it take the wheel to make one revolution?
(a) 0.33 s (b) 2.4 s (c) 10 s (d) 0.66 s (d) 6.1 s

Question

A 50-N ⋅ m torque acts on a wheel with a moment of inertia 150 kg ⋅ m2.  If the wheel starts from rest, how long will it take the wheel to make one revolution?
	(a)	0.33 s	(b) 2.4 s			(c) 10 s		(d) 0.66 s	 (d) 6.1 s

vincent-lyon.fr · Answer

This is basic application of kinematics concerning rotation and angular acceleration.
What do you think?

anonymous · Answer

im not sure of the formula to use for angular acceleration?

anonymous · Answer

torque=MOMENT OF INERTIA*angular acceleration

vincent-lyon.fr · Answer

The formulae are the same as those for linear acceleration:

Substitute:
Torque τ for Force F
Moment of inertia I for Mass m
Angular acceleration α for Linear acceleration a

Then substitute:

Angular velocity ω for Linear velocity v
Angular displacement θ for Linear displacement s (or x)

anonymous · Answer

Remember formula:  	au = I*\alpha.  Solve for \alpha.  Then 2*\pi = 1/2*\alpha*t^2 and solve for t.