Question

what is the factor of x2-6x-8

Answer 1

are you sure the last nummber is 08?

Answer 2

-8 *

Answer 3

yes

Answer 4

i doubt it's factorable then

Answer 5

i dont know

Answer 6

are you sure @Wired ?

Answer 7

4 times 2

Answer 8

4+2=6 and 4x2=8

Answer 9

if you have written this correctly @elainediaz then it is not factorable because the only factors of 8 that add up to -6 is -4 x -2

and that results to POSITIVE 8 not negative

Answer 10

Bah, same damn typo twice lol.
\[(x+a)(x-b) = x^{2}+ax-bx-ab = x^{2}+(a-b)x-ab\]

Yeah, not factorable.

Answer 11

ok its not factorable

Answer 12

lol

Answer 13

i di positive

Answer 14

This would be consistent with finding a complex root. Use the quadratic formula to find the root values of \[x ^{2} - 6x - 8; a = 1, b = -6, c = -8\]

Answer 15

Quadratic formula
\[- b \pm \sqrt{b^2 -4ac}\div2a\]

Answer 16

@jenxcc question is to factorize and not to find the values of x..

Answer 17

Factorizing this cannot be factored as a real root, true, but can be as a complex root.
So, \[(x-(3+\sqrt{17})(x-(3-\sqrt{17})\]

Answer 18

\[\LARGE{\color{red}{\frac{-b \sqrt{b^2-4ac}}{2a}}}\]

Answer 19

use this & get ur ans:)